यदि \(2x^2+3x-5=0\) की जड़ें \(\alpha,\beta\) हैं, तो \(\alpha^2\beta+\alpha\beta^2\) का मान क्या है?
If \(\alpha,\beta\) are roots of \(2x^2+3x-5=0\), what is \(\alpha^2\beta+\alpha\beta^2\)?
Explanation opens after your attempt
Correct Answer
A. \(\frac{15}{4}\)
Concept
(\alpha-2\beta+\alpha\beta-2=\alpha\beta\(\alpha+\beta\)). Since \(\alpha\beta=-\frac{5}{2}\) and \(\alpha+\beta=-\frac{3}{2}\), the value is \(\frac{15}{4}\).
Why this answer is correct
The correct answer is A. \(\frac{15}{4}\). (\alpha-2\beta+\alpha\beta-2=\alpha\beta\(\alpha+\beta\)). Since \(\alpha\beta=-\frac{5}{2}\) and \(\alpha+\beta=-\frac{3}{2}\), the value is \(\frac{15}{4}\).
Exam Tip
(\alpha-2\beta+\alpha\beta-2=\alpha\beta\(\alpha+\beta\)) होता है। \(\alpha\beta=-\frac{5}{2}\) और \(\alpha+\beta=-\frac{3}{2}\), इसलिए मान \(\frac{15}{4}\) है।
Login to save your score, XP, coins and progress.