Hard Mathematics Quadratic Equations Class 10 Level 30

यदि \(x^2+7x+10=0\) के मूल \(\alpha\) और \(\beta\) हैं, तो (\(\alpha+2\)\(\beta+2\)) का मान क्या है?

If \(\alpha\) and \(\beta\) are roots of \(x^2+7x+10=0\), what is (\(\alpha+2\)\(\beta+2\))?

Explanation opens after your attempt
Correct Answer

A. (0)

Step 1

Concept

(\(\alpha+2\)\(\beta+2\)=\alpha\beta+2\(\alpha+\beta\)+4). Here (10+2(-7)+4=0).

Step 2

Why this answer is correct

The correct answer is A. (0). (\(\alpha+2\)\(\beta+2\)=\alpha\beta+2\(\alpha+\beta\)+4). Here (10+2(-7)+4=0).

Step 3

Exam Tip

(\(\alpha+2\)\(\beta+2\)=\alpha\beta+2\(\alpha+\beta\)+4) होता है। यहाँ (10+2(-7)+4=0)।

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Mathematics Answer, Explanation and Revision Hints

यदि \(x^2+7x+10=0\) के मूल \(\alpha\) और \(\beta\) हैं, तो (\(\alpha+2\)\(\beta+2\)) का मान क्या है? / If \(\alpha\) and \(\beta\) are roots of \(x^2+7x+10=0\), what is (\(\alpha+2\)\(\beta+2\))?

Correct Answer: A. (0). Explanation: (\(\alpha+2\)\(\beta+2\)=\alpha\beta+2\(\alpha+\beta\)+4) होता है। यहाँ (10+2(-7)+4=0)। / (\(\alpha+2\)\(\beta+2\)=\alpha\beta+2\(\alpha+\beta\)+4). Here (10+2(-7)+4=0).

Which concept should I revise for this Mathematics MCQ?

(\(\alpha+2\)\(\beta+2\)=\alpha\beta+2\(\alpha+\beta\)+4). Here (10+2(-7)+4=0).

What exam hint can help solve this Mathematics question?

(\(\alpha+2\)\(\beta+2\)=\alpha\beta+2\(\alpha+\beta\)+4) होता है। यहाँ (10+2(-7)+4=0)।

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