यदि \(a_n=8\cdot2^{n-1}\) है, तो यह कौन-सा अनुक्रम बनाता है?
If \(a_n=8\cdot2^{n-1}\), which sequence does it form?
Explanation opens after your attempt
C. \(8,16,32,64,\ldots\)
Concept
Putting (n=1,2,3,4) gives (8,16,32,64). Form the initial terms from the rule and match the option.
Why this answer is correct
The correct answer is C. \(8,16,32,64,\ldots\). Putting (n=1,2,3,4) gives (8,16,32,64). Form the initial terms from the rule and match the option.
Exam Tip
(n=1,2,3,4) रखने पर (8,16,32,64) मिलते हैं। नियम से शुरू के पद बनाकर विकल्प मिलाएं।
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