Medium Mathematics Sequences and Progressions Class 9 Level 48

यदि \(a_n=3n^2+2n-1\) है तो कौन-सा कथन सही है?

If \(a_n=3n^2+2n-1\) then which statement is correct?

Explanation opens after your attempt
Correct Answer

A. \(a_2=15\) और \(a_3=32\)\(a_2=15\) and \(a_3=32\)

Step 1

Concept

\(a_2=12+4-1=15\) and \(a_3=27+6-1=32\). In exams use a new value of (n) for each term.

Step 2

Why this answer is correct

The correct answer is A. \(a_2=15\) और \(a_3=32\) / \(a_2=15\) and \(a_3=32\). \(a_2=12+4-1=15\) and \(a_3=27+6-1=32\). In exams use a new value of (n) for each term.

Step 3

Exam Tip

\(a_2=12+4-1=15\) और \(a_3=27+6-1=32\) है। परीक्षा में हर पद के लिए (n) का नया मान रखें।

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FAQs

Mathematics Answer, Explanation and Revision Hints

यदि \(a_n=3n^2+2n-1\) है तो कौन-सा कथन सही है? / If \(a_n=3n^2+2n-1\) then which statement is correct?

Correct Answer: A. \(a_2=15\) और \(a_3=32\) / \(a_2=15\) and \(a_3=32\). Explanation: \(a_2=12+4-1=15\) और \(a_3=27+6-1=32\) है। परीक्षा में हर पद के लिए (n) का नया मान रखें। / \(a_2=12+4-1=15\) and \(a_3=27+6-1=32\). In exams use a new value of (n) for each term.

Which concept should I revise for this Mathematics MCQ?

\(a_2=12+4-1=15\) and \(a_3=27+6-1=32\). In exams use a new value of (n) for each term.

What exam hint can help solve this Mathematics question?

\(a_2=12+4-1=15\) और \(a_3=27+6-1=32\) है। परीक्षा में हर पद के लिए (n) का नया मान रखें।

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