If \(a_n=3n^2+2n-1\) then which statement is correct?
Explanation opens after your attempt
Correct Answer
A. \(a_2=15\) और \(a_3=32\)/\(a_2=15\) and \(a_3=32\)
Step 1
Concept
\(a_2=12+4-1=15\) and \(a_3=27+6-1=32\). In exams use a new value of (n) for each term.
Step 2
Why this answer is correct
The correct answer is A. \(a_2=15\) और \(a_3=32\) / \(a_2=15\) and \(a_3=32\). \(a_2=12+4-1=15\) and \(a_3=27+6-1=32\). In exams use a new value of (n) for each term.
Step 3
Exam Tip
\(a_2=12+4-1=15\) और \(a_3=27+6-1=32\) है। परीक्षा में हर पद के लिए (n) का नया मान रखें।
Mathematics Answer, Explanation and Revision Hints
यदि \(a_n=3n^2+2n-1\) है तो कौन-सा कथन सही है? / If \(a_n=3n^2+2n-1\) then which statement is correct?
Correct Answer: A. \(a_2=15\) और \(a_3=32\) / \(a_2=15\) and \(a_3=32\). Explanation: \(a_2=12+4-1=15\) और \(a_3=27+6-1=32\) है। परीक्षा में हर पद के लिए (n) का नया मान रखें। / \(a_2=12+4-1=15\) and \(a_3=27+6-1=32\). In exams use a new value of (n) for each term.
Which concept should I revise for this Mathematics MCQ?
\(a_2=12+4-1=15\) and \(a_3=27+6-1=32\). In exams use a new value of (n) for each term.
What exam hint can help solve this Mathematics question?
\(a_2=12+4-1=15\) और \(a_3=27+6-1=32\) है। परीक्षा में हर पद के लिए (n) का नया मान रखें।
Login to view answers
Use Google login or mobile OTP. Admin can block users and control login providers.
Student Class Required
Select your class first
Quiz questions, daily challenge and practice pages will open according to your selected class. Class 11/12 ke liye stream bhi select karein.