यदि ((a+1)x-2+\(a^2-1\)x+2=0) में (a=-1) हो, तो समीकरण किस प्रकार का होगा?
If (a=-1) in ((a+1)x-2+\(a^2-1\)x+2=0), what type of equation will it be?
Explanation opens after your attempt
C. विरोधाभासी कथनContradictory statement
Concept
Putting (a=-1) gives \(0x^2+0x+2=0\). This is (2=0), which is a contradictory statement.
Why this answer is correct
The correct answer is C. विरोधाभासी कथन / Contradictory statement. Putting (a=-1) gives \(0x^2+0x+2=0\). This is (2=0), which is a contradictory statement.
Exam Tip
(a=-1) रखने पर \(0x^2+0x+2=0\) मिलता है। यह (2=0) है, जो विरोधाभासी कथन है।
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