यदि ((5-p)x-2+2x+9=0) द्विघात समीकरण है, तो (p) के लिए सही शर्त क्या है?
If ((5-p)x-2+2x+9=0) is a quadratic equation, what is the correct condition for (p)?
Explanation opens after your attempt
B. \(p\neq 5\)
Concept
For a quadratic equation, the coefficient of \(x^2\) must not be (0). Thus \(5-p\neq0\), so \(p\neq5\).
Why this answer is correct
The correct answer is B. \(p\neq 5\). For a quadratic equation, the coefficient of \(x^2\) must not be (0). Thus \(5-p\neq0\), so \(p\neq5\).
Exam Tip
द्विघात समीकरण के लिए \(x^2\) का गुणांक (0) नहीं होना चाहिए। इसलिए \(5-p\neq0\), अर्थात \(p\neq5\)।
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