किस मान पर (\(a^2-16\)x+7) रेखीय बहुपद नहीं रहेगा?
For which value will (\(a^2-16\)x+7) not remain a linear polynomial?
Explanation opens after your attempt
Correct Answer
B. (a=4) या (a=-4)/(a=4) or (a=-4)
Step 1
Concept
For it not to be linear, the coefficient of (x) must be (0). From \(a^2-16=0\), \(a=\pm4\).
Step 2
Why this answer is correct
The correct answer is B. (a=4) या (a=-4) / (a=4) or (a=-4). For it not to be linear, the coefficient of (x) must be (0). From \(a^2-16=0\), \(a=\pm4\).
Step 3
Exam Tip
रेखीय न रहने के लिए (x) का गुणांक (0) होना चाहिए। \(a^2-16=0\) से \(a=\pm4\) मिलता है।
Mathematics Answer, Explanation and Revision Hints
किस मान पर (\(a^2-16\)x+7) रेखीय बहुपद नहीं रहेगा? / For which value will (\(a^2-16\)x+7) not remain a linear polynomial?
Correct Answer: B. (a=4) या (a=-4) / (a=4) or (a=-4). Explanation: रेखीय न रहने के लिए (x) का गुणांक (0) होना चाहिए। \(a^2-16=0\) से \(a=\pm4\) मिलता है। / For it not to be linear, the coefficient of (x) must be (0). From \(a^2-16=0\), \(a=\pm4\).
Which concept should I revise for this Mathematics MCQ?
For it not to be linear, the coefficient of (x) must be (0). From \(a^2-16=0\), \(a=\pm4\).
What exam hint can help solve this Mathematics question?
रेखीय न रहने के लिए (x) का गुणांक (0) होना चाहिए। \(a^2-16=0\) से \(a=\pm4\) मिलता है।
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