किस मान पर (\(a^2-16\)x+7) रेखीय बहुपद नहीं रहेगा?

For which value will (\(a^2-16\)x+7) not remain a linear polynomial?

Explanation opens after your attempt
Correct Answer

B. (a=4) या (a=-4)(a=4) or (a=-4)

Step 1

Concept

For it not to be linear, the coefficient of (x) must be (0). From \(a^2-16=0\), \(a=\pm4\).

Step 2

Why this answer is correct

The correct answer is B. (a=4) या (a=-4) / (a=4) or (a=-4). For it not to be linear, the coefficient of (x) must be (0). From \(a^2-16=0\), \(a=\pm4\).

Step 3

Exam Tip

रेखीय न रहने के लिए (x) का गुणांक (0) होना चाहिए। \(a^2-16=0\) से \(a=\pm4\) मिलता है।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

किस मान पर (\(a^2-16\)x+7) रेखीय बहुपद नहीं रहेगा? / For which value will (\(a^2-16\)x+7) not remain a linear polynomial?

Correct Answer: B. (a=4) या (a=-4) / (a=4) or (a=-4). Explanation: रेखीय न रहने के लिए (x) का गुणांक (0) होना चाहिए। \(a^2-16=0\) से \(a=\pm4\) मिलता है। / For it not to be linear, the coefficient of (x) must be (0). From \(a^2-16=0\), \(a=\pm4\).

Which concept should I revise for this Mathematics MCQ?

For it not to be linear, the coefficient of (x) must be (0). From \(a^2-16=0\), \(a=\pm4\).

What exam hint can help solve this Mathematics question?

रेखीय न रहने के लिए (x) का गुणांक (0) होना चाहिए। \(a^2-16=0\) से \(a=\pm4\) मिलता है।

Student Class Required

Select your class first

Quiz questions, daily challenge and practice pages will open according to your selected class. Class 11/12 ke liye stream bhi select karein.