एक विलेय के (1.0,g) को (500,g) जल में घोलने पर \(\Delta T_f=0.0186,K\) है। यदि (i=1), तो मोलर द्रव्यमान क्या होगा?
When (1.0,g) solute is dissolved in (500,g) water, \(\Delta T_f=0.0186,K\). If (i=1), what is the molar mass?
Correct answer and explanation
C. \(200,g,mol^{-1}\)
Concept
\(m=\frac{0.0186}{1.86}=0.01\)। / \(m=\frac{0.0186}{1.86}=0.01\).
Why this answer is correct
(500,g=0.5,kg), इसलिए मोल \(0.01\times0.5=0.005\) हैं। / (500,g=0.5,kg), so moles \(=0.01\times0.5=0.005\).
Exam Tip
मोलर द्रव्यमान \(\frac{1.0}{0.005}=200,g,mol^{-1}\)। / Molar mass \(=\frac{1.0}{0.005}=200,g,mol^{-1}\).
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