यदि (0.5,g) विलेय (50,g) जल में घोलने पर \(\Delta T_f=0.186,K\) देता है, तो \(K_f=1.86,K,kg,mol^{-1}\) मानकर मोलर द्रव्यमान क्या है?
If (0.5,g) solute dissolved in (50,g) water gives \(\Delta T_f=0.186,K\), what is the molar mass taking \(K_f=1.86,K,kg,mol^{-1}\)?
Correct answer and explanation
C. \(100,g,mol^{-1}\)
Concept
\(m=\frac{0.186}{1.86}=0.1\) है। / \(m=\frac{0.186}{1.86}=0.1\).
Why this answer is correct
\(50,g=0.05,kg\), इसलिए मोल \(0.1\times0.05=0.005\) हैं। / \(50,g=0.05,kg\), so moles \(=0.1\times0.05=0.005\).
Exam Tip
मोलर द्रव्यमान \(=\frac{0.5}{0.005}=100,g,mol^{-1}\)। / Molar mass \(=\frac{0.5}{0.005}=100,g,mol^{-1}\).
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