Which option is not constant and represents linear decay with (x)?
Answer and explanation
Correct answer: \(y=45-3x\)
In linear decay, the power of \(x\) is 1 and its coefficient is negative. In \(y=45-3x\), the coefficient of \(x\) is \(-3\), so \(y\) decreases by 3 for every one-unit increase in \(x\). \(y=45+3x\) shows linear growth, while \(y=45-3x^2\) is quadratic rather than linear. Exam tip: for \(y=a+bx\), check that \(b<0\) to identify linear decay.
Frequently asked questions
What is the correct answer to this question?
\(y=45-3x\)
Why is this the correct answer?
In linear decay, the power of \(x\) is 1 and its coefficient is negative. In \(y=45-3x\), the coefficient of \(x\) is \(-3\), so \(y\) decreases by 3 for every one-unit increase in \(x\). \(y=45+3x\) shows linear growth, while \(y=45-3x^2\) is quadratic rather than linear. Exam tip: for \(y=a+bx\), check that \(b<0\) to identify linear decay.
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Introduction to Polynomials. Topic: Linear growth and decay.
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