Which is the sum of the first (16) natural numbers?
Answer and explanation
Correct answer: 136
The sum of the first \(n\) natural numbers is \(S_n=\frac{n(n+1)}{2}\). Therefore, \(S_{16}=\frac{16\times17}{2}=8\times17=136\). Hence, 136 is correct. A value such as 132 results from an incorrect calculation of \(16\times17\) divided by 2. Exam tip: divide the even factor by 2 first to calculate quickly.
Frequently asked questions
What is the correct answer to this question?
136
Why is this the correct answer?
The sum of the first \(n\) natural numbers is \(S_n=\frac{n(n+1)}{2}\). Therefore, \(S_{16}=\frac{16\times17}{2}=8\times17=136\). Hence, 136 is correct. A value such as 132 results from an incorrect calculation of \(16\times17\) divided by 2. Exam tip: divide the even factor by 2 first to calculate quickly.
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Sum of first n natural numbers.
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