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Class 9MathematicsSequences and ProgressionsSum of first n natural numbersEasyLevel 63
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Which is the general formula for (1+2+3+\cdots+n)?

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Answer and explanation

Correct answer: (\frac{n(n+1)}{2})

The sum of the first (n) natural numbers is (S_n=\frac{n(n+1)}{2}). This formula is the key formula of this topic.

Related tags

MathSequencesNatural-NumbersSum

Frequently asked questions

What is the correct answer to this question?

(\frac{n(n+1)}{2})

Why is this the correct answer?

The sum of the first (n) natural numbers is (S_n=\frac{n(n+1)}{2}). This formula is the key formula of this topic.

Which subject and chapter does this question cover?

This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Sum of first n natural numbers.

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10 more MCQs
  1. 1Let A = {x : x is a natural number and x < 4}. What is A?
  2. 2What will be the 9th term in the sequence (3, −6, 12, −24, …)?
  3. 3If (a=10) and (d=2), what will be the sum of the first (6) terms?
  4. 4If a = 7 and d = 3, what is the sum of the first 6 terms?
  5. 5What is the sum of the first 6 terms of the arithmetic progression (15, 21, 27, 33, ...)?
  6. 6What is the sum of the first (10) natural numbers?
  7. 7Find the sum of the first (20) natural numbers.
  8. 8If \(S_n=\frac{n(n+1)}{2}\), what is \(S_{15}\)?
  9. 9What is the value of (1+2+3+\cdots+25)?
  10. 10Which is the sum of the first (30) natural numbers?
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