What will be the sum of the first (95) natural numbers?
Answer and explanation
Correct answer: 4560
The sum of the first \(n\) natural numbers is \(\frac{n(n+1)}{2}\). Substituting \(n=95\), we get \(\frac{95\times96}{2}=95\times48=4560\). Therefore, option C is correct. A value such as \(4550\) may result from an error while multiplying the middle terms. Exam tip: cancel 2 with the even factor before multiplying.
Frequently asked questions
What is the correct answer to this question?
4560
Why is this the correct answer?
The sum of the first \(n\) natural numbers is \(\frac{n(n+1)}{2}\). Substituting \(n=95\), we get \(\frac{95\times96}{2}=95\times48=4560\). Therefore, option C is correct. A value such as \(4550\) may result from an error while multiplying the middle terms. Exam tip: cancel 2 with the even factor before multiplying.
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Sum of first n natural numbers.
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