What will be the sum of the first (41) natural numbers?
Answer and explanation
Correct answer: 861
The sum of the first \(n\) natural numbers is \(S_n=\frac{n(n+1)}{2}\). Therefore, \(S_{41}=\frac{41\times42}{2}=41\times21=861\). Hence, 861 is the correct answer. A value such as 841 is less than the correct product \(41\times21\). Exam tip: Cancel 2 with the even factor first to calculate quickly.
Frequently asked questions
What is the correct answer to this question?
861
Why is this the correct answer?
The sum of the first \(n\) natural numbers is \(S_n=\frac{n(n+1)}{2}\). Therefore, \(S_{41}=\frac{41\times42}{2}=41\times21=861\). Hence, 861 is the correct answer. A value such as 841 is less than the correct product \(41\times21\). Exam tip: Cancel 2 with the even factor first to calculate quickly.
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Sum of first n natural numbers.
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