अनुक्रम \(3,6,10,15,21,\ldots\) में (20)वाँ पद क्या होगा?

What will be the (20)th term in the sequence \(3,6,10,15,21,\ldots\)?

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Correct Answer

C. (231)

Step 1

Concept

This sequence gives (\frac{(n+1)(n+2)}{2}). For the (20)th term, \(\frac{21\times22}{2}=231\).

Step 2

Why this answer is correct

The correct answer is C. (231). This sequence gives (\frac{(n+1)(n+2)}{2}). For the (20)th term, \(\frac{21\times22}{2}=231\).

Step 3

Exam Tip

यह अनुक्रम (\frac{(n+1)(n+2)}{2}) देता है। (20)वें पद के लिए \(\frac{21\times22}{2}=231\) होगा।

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Mathematics Answer, Explanation and Revision Hints

अनुक्रम \(3,6,10,15,21,\ldots\) में (20)वाँ पद क्या होगा? / What will be the (20)th term in the sequence \(3,6,10,15,21,\ldots\)?

Correct Answer: C. (231). Explanation: यह अनुक्रम (\frac{(n+1)(n+2)}{2}) देता है। (20)वें पद के लिए \(\frac{21\times22}{2}=231\) होगा। / This sequence gives (\frac{(n+1)(n+2)}{2}). For the (20)th term, \(\frac{21\times22}{2}=231\).

Which concept should I revise for this Mathematics MCQ?

This sequence gives (\frac{(n+1)(n+2)}{2}). For the (20)th term, \(\frac{21\times22}{2}=231\).

What exam hint can help solve this Mathematics question?

यह अनुक्रम (\frac{(n+1)(n+2)}{2}) देता है। (20)वें पद के लिए \(\frac{21\times22}{2}=231\) होगा।