What is the value of (41^2)?
Answer and explanation
Correct answer: 1681
The square of 41 is \(41^2=41\times41\). Since \(40\times41=1640\) and \(1\times41=41\), the total is \(1640+41=1681\). Therefore, 1681 is correct. A value such as 1661 can result from a small addition or multiplication error. Exam tip: use \((a+1)^2=a^2+2a+1\), so \(41^2=(40+1)^2=1600+80+1=1681\).
Frequently asked questions
What is the correct answer to this question?
1681
Why is this the correct answer?
The square of 41 is \(41^2=41\times41\). Since \(40\times41=1640\) and \(1\times41=41\), the total is \(1640+41=1681\). Therefore, 1681 is correct. A value such as 1661 can result from a small addition or multiplication error. Exam tip: use \((a+1)^2=a^2+2a+1\), so \(41^2=(40+1)^2=1600+80+1=1681\).
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Number Systems. Topic: Exponents.
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