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What is the value of (41^2)?(41^2) का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: 16811681
The square of 41 is \(41^2=41\times41\). Since \(40\times41=1640\) and \(1\times41=41\), the total is \(1640+41=1681\). Therefore, 1681 is correct. A value such as 1661 can result from a small addition or multiplication error. Exam tip: use \((a+1)^2=a^2+2a+1\), so \(41^2=(40+1)^2=1600+80+1=1681\).यहाँ 41 का वर्ग निकालना है: \(41^2=41\times41\)। \(40\times41=1640\) और \(1\times41=41\), इसलिए \(1640+41=1681\)। अतः सही उत्तर 1681 है। 1661 जैसे विकल्प जोड़ या गुणा में छोटी गलती से आ सकते हैं। परीक्षा टिप: \((a+1)^2=a^2+2a+1\) से भी \(41^2=(40+1)^2=1600+80+1=1681\) निकाल सकते हैं।
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