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What is the value of \(28^2+29^2\)?

Answer and explanation

Correct answer: 1625

Use the identity \(a^2+b^2=(a+b)^2-2ab\) for a quick calculation. With \(a=28, b=29\): \(a+b=57\) and \(ab=28\times29=812\). So \(28^2+29^2=57^2-2\times812=3249-1624=1625\). The close option 1615 is incorrect — it could arise from miscalculating \(29^2\) as 831 instead of 841. Exam tip: either use the identity above or compute \(28^2=784\) and \(29^2=841\) separately and add them to avoid small arithmetic mistakes.

Related tags

ExponentsSquaresNumber-SystemsMental-MathNumber SystemsMathematicsClass 9 Mcq

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