What is the sum of the first (70) natural numbers?
Answer and explanation
Correct answer: 2485
The sum of the first \(n\) natural numbers is \(\frac{n(n+1)}{2}\). Substituting \(n=70\), we get \(\frac{70\times71}{2}=35\times71=2485\). Therefore, 2485 is correct. A value such as 2475 results from an arithmetic error in multiplication or addition. Exam tip: cancel 2 with an even factor in \(n(n+1)\) before multiplying.
Frequently asked questions
What is the correct answer to this question?
2485
Why is this the correct answer?
The sum of the first \(n\) natural numbers is \(\frac{n(n+1)}{2}\). Substituting \(n=70\), we get \(\frac{70\times71}{2}=35\times71=2485\). Therefore, 2485 is correct. A value such as 2475 results from an arithmetic error in multiplication or addition. Exam tip: cancel 2 with an even factor in \(n(n+1)\) before multiplying.
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Sum of first n natural numbers.
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