What is the sum of the first (47) natural numbers?
Answer and explanation
Correct answer: 1128
The sum of the first \(n\) natural numbers is \(\frac{n(n+1)}{2}\). Substituting \(n=47\), we get \(\frac{47\times48}{2}=47\times24=1128\). Therefore, option B is correct. A value such as \(1104\) can result from using an incorrect number of terms or multiplication. Exam tip: always write both \(n\) and \(n+1\) in the formula.
Frequently asked questions
What is the correct answer to this question?
1128
Why is this the correct answer?
The sum of the first \(n\) natural numbers is \(\frac{n(n+1)}{2}\). Substituting \(n=47\), we get \(\frac{47\times48}{2}=47\times24=1128\). Therefore, option B is correct. A value such as \(1104\) can result from using an incorrect number of terms or multiplication. Exam tip: always write both \(n\) and \(n+1\) in the formula.
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Sum of first n natural numbers.
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