What is the sum of the first (43) natural numbers?
Answer and explanation
Correct answer: 946
The sum of the first \(n\) natural numbers is \(\frac{n(n+1)}{2}\). Substituting \(n=43\), we get \(\frac{43\times44}{2}=43\times22=946\). Hence, option B is correct. A value such as \(903\) may be associated with the sum up to \(42\), but the question asks for the sum up to \(43\). Exam tip: Divide the even factor \(44\) by 2 before multiplying to calculate faster.
Frequently asked questions
What is the correct answer to this question?
946
Why is this the correct answer?
The sum of the first \(n\) natural numbers is \(\frac{n(n+1)}{2}\). Substituting \(n=43\), we get \(\frac{43\times44}{2}=43\times22=946\). Hence, option B is correct. A value such as \(903\) may be associated with the sum up to \(42\), but the question asks for the sum up to \(43\). Exam tip: Divide the even factor \(44\) by 2 before multiplying to calculate faster.
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Sum of first n natural numbers.
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