What is the sum of the first (40) natural numbers?
Answer and explanation
Correct answer: 820
The sum of the first \(n\) natural numbers is \(S_n=\frac{n(n+1)}{2}\). Therefore, \(S_{40}=\frac{40\times41}{2}=20\times41=820\). Hence, 820 is correct. An answer such as 800 may result from incorrectly using 40 in place of \(n+1\). Exam tip: Write \(n(n+1)/2\) before substituting the value of \(n\).
Frequently asked questions
What is the correct answer to this question?
820
Why is this the correct answer?
The sum of the first \(n\) natural numbers is \(S_n=\frac{n(n+1)}{2}\). Therefore, \(S_{40}=\frac{40\times41}{2}=20\times41=820\). Hence, 820 is correct. An answer such as 800 may result from incorrectly using 40 in place of \(n+1\). Exam tip: Write \(n(n+1)/2\) before substituting the value of \(n\).
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Sum of first n natural numbers.
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