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What is the (6)th term of (64,125,216,343,\ldots)?क्रम (64,125,216,343,\ldots) का (6)ठा पद क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: 729729
The terms are \(4^3, 5^3, 6^3, 7^3, \ldots\), respectively. Hence, the fifth term is \(8^3=512\), while the sixth term is \(9^3=729\). Therefore, 729 is correct. In exams, first identify the sequence of base numbers and then apply the exponent.दिए गए पद क्रमशः \(4^3, 5^3, 6^3, 7^3, \ldots\) हैं। इसलिए पाँचवाँ पद \(8^3=512\) और छठा पद \(9^3=729\) होगा। अतः सही उत्तर 729 है। परीक्षा में ऐसे क्रमों में पहले आधार संख्याओं का क्रम पहचानें, फिर घात लागू करें।
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