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What is the (5)th term of (8,27,64,125,\ldots)?क्रम (8,27,64,125,\ldots) का (5)वाँ पद क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: 216216
The given terms are consecutive cubes: \(8=2^3\), \(27=3^3\), \(64=4^3\), and \(125=5^3\). Therefore, the next, or fifth, term is \(6^3=216\). \(225\) is not a cube number, so it cannot be the next term of this sequence. Exam tip: Rewrite sequence terms as cubes to identify the pattern in their bases.दिए गए पद क्रमशः घन संख्याएँ हैं: \(8=2^3\), \(27=3^3\), \(64=4^3\) और \(125=5^3\)। इसलिए अगला, अर्थात पाँचवाँ पद \(6^3=216\) होगा। \(225\) घन संख्या नहीं है, इसलिए वह इस क्रम का अगला पद नहीं हो सकता। परीक्षा टिप: ऐसे क्रम में प्रत्येक पद को घन के रूप में लिखकर आधार संख्याओं का क्रम पहचानें।
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