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What is simplified form of (\frac{1}{(a^{-2} b^3)})

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Answer and explanation

Correct answer: \(\frac{a^2}{b^3}\)

In the given expression, \(a^{-2}\) is in the denominator. Using the rule \(a^{-n}=\frac{1}{a^n}\), we get \(\frac{1}{a^{-2}b^3}=\frac{a^2}{b^3}\). Therefore, option A is correct. Exam tip: when a factor with a negative exponent moves across a fraction bar, the sign of its exponent changes, while \(b^3\) remains in the denominator.

Related tags

ExponentsLaws Of ExponentsNegative ExponentsNumber SystemsAlgebraic Simplification

Frequently asked questions

What is the correct answer to this question?

\(\frac{a^2}{b^3}\)

Why is this the correct answer?

In the given expression, \(a^{-2}\) is in the denominator. Using the rule \(a^{-n}=\frac{1}{a^n}\), we get \(\frac{1}{a^{-2}b^3}=\frac{a^2}{b^3}\). Therefore, option A is correct. Exam tip: when a factor with a negative exponent moves across a fraction bar, the sign of its exponent changes, while \(b^3\) remains in the denominator.

Which subject and chapter does this question cover?

This is a Class 9 Mathematics question. Chapter: Number Systems. Topic: Exponents.

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