Two models are (C(t)=140-8t) and (D(t)=110-3t). What is the correct comparison at (t=6)?
Answer and explanation
Correct answer: \(C(6)=D(6)\)
Substituting \(t=6\), \(C(6)=140-8\times6=92\) and \(D(6)=110-3\times6=92\). Hence, the two model values are equal, so \(C(6)=D(6)\). Options A and B are incorrect because neither value is greater than the other, and both values are not zero. Exam tip: evaluate each expression separately at the given value of \(t\) before comparing them.
Frequently asked questions
What is the correct answer to this question?
\(C(6)=D(6)\)
Why is this the correct answer?
Substituting \(t=6\), \(C(6)=140-8\times6=92\) and \(D(6)=110-3\times6=92\). Hence, the two model values are equal, so \(C(6)=D(6)\). Options A and B are incorrect because neither value is greater than the other, and both values are not zero. Exam tip: evaluate each expression separately at the given value of \(t\) before comparing them.
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Introduction to Polynomials. Topic: Linear growth and decay.
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