Two models are (A(t)=15+4t) and (B(t)=35+2t). Which value is greater at (t=6)?
Answer and explanation
Correct answer: The value of model B is greater
Substituting t=6 gives A(6)=15+4×6=39 and B(6)=35+2×6=47. Since 47 is greater than 39, the value of model B is greater. Although model A has a higher growth rate, its lower initial value means that it has not overtaken B at t=6. Exam tip: substitute the same value of t into both expressions and compare the resulting numbers directly.
Frequently asked questions
What is the correct answer to this question?
The value of model B is greater
Why is this the correct answer?
Substituting t=6 gives A(6)=15+4×6=39 and B(6)=35+2×6=47. Since 47 is greater than 39, the value of model B is greater. Although model A has a higher growth rate, its lower initial value means that it has not overtaken B at t=6. Exam tip: substitute the same value of t into both expressions and compare the resulting numbers directly.
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Introduction to Polynomials. Topic: Linear growth and decay.
Student feedback
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
