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Two models are (A(t)=10+3t) and (B(t)=25+t). What is the correct comparison at (t=5)?

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Answer and explanation

Correct answer: \(B(5)>A(5)\)

Substituting \(t=5\), we get \(A(5)=10+3(5)=25\) and \(B(5)=25+5=30\). Since \(30>25\), \(B(5)>A(5)\) is correct. \(A(5)=B(5)\) is incorrect because the values differ by 5. Exam tip: Substitute the given value of \(t\) into each expression separately before comparing them.

Related tags

PolynomialsLinear ModelsSubstitutionComparisonLinear Growth

Frequently asked questions

What is the correct answer to this question?

\(B(5)>A(5)\)

Why is this the correct answer?

Substituting \(t=5\), we get \(A(5)=10+3(5)=25\) and \(B(5)=25+5=30\). Since \(30>25\), \(B(5)>A(5)\) is correct. \(A(5)=B(5)\) is incorrect because the values differ by 5. Exam tip: Substitute the given value of \(t\) into each expression separately before comparing them.

Which subject and chapter does this question cover?

This is a Class 9 Mathematics question. Chapter: Introduction to Polynomials. Topic: Linear growth and decay.

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