The sum of the first (44) natural numbers is equal to which value?
Answer and explanation
Correct answer: 990
The sum of the first \(n\) natural numbers is \(\frac{n(n+1)}{2}\). Substituting \(n=44\), we get \(\frac{44\times45}{2}=22\times45=990\). Therefore, 990 is correct. A value such as 968 may result from incorrectly using \(44\times44/2\); the formula must include \(n+1\). Exam tip: When \(n\) is even, divide it by 2 first for quicker calculation.
Frequently asked questions
What is the correct answer to this question?
990
Why is this the correct answer?
The sum of the first \(n\) natural numbers is \(\frac{n(n+1)}{2}\). Substituting \(n=44\), we get \(\frac{44\times45}{2}=22\times45=990\). Therefore, 990 is correct. A value such as 968 may result from incorrectly using \(44\times44/2\); the formula must include \(n+1\). Exam tip: When \(n\) is even, divide it by 2 first for quicker calculation.
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Sum of first n natural numbers.
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