किसी अनुक्रम के पहले चार पद (4), (10), (22), (46) हैं और नियम \(a_n=2a_{n-1}+2\) है। \(a_5\) क्या होगा?
The first four terms of a sequence are (4), (10), (22), (46), and the rule is \(a_n=2a_{n-1}+2\). What is \(a_5\)?
Explanation opens after your attempt
B. चौरानवे(94)
Concept
\(a_5=2\times 46+2=94\). In exams, apply the rule to the last given term.
Why this answer is correct
The correct answer is B. चौरानवे / (94). \(a_5=2\times 46+2=94\). In exams, apply the rule to the last given term.
Exam Tip
\(a_5=2\times 46+2=94\) है। परीक्षा में अंतिम दिए पद पर नियम लगाएँ।
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