क्या \(-\sqrt{2}x+9\) (x) में बहुपद है?
Is \(-\sqrt{2}x+9\) a polynomial in (x)?
Explanation opens after your attempt
Correct Answer
A. हां, क्योंकि \(-\sqrt{2}\) वास्तविक गुणांक हैYes, because \(-\sqrt{2}\) is a real coefficient
Concept
Coefficients can be real numbers. Here the power of (x) is (1), so it is a polynomial.
Why this answer is correct
The correct answer is A. हां, क्योंकि \(-\sqrt{2}\) वास्तविक गुणांक है / Yes, because \(-\sqrt{2}\) is a real coefficient. Coefficients can be real numbers. Here the power of (x) is (1), so it is a polynomial.
Exam Tip
गुणांक वास्तविक संख्या हो सकते हैं। यहां (x) की घात (1) है, इसलिए यह बहुपद है।
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