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In the sequence (\frac{1}{3},\frac{1}{6},\frac{1}{9},\ldots), which is the first term less than (\frac{1}{50})?
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Answer and explanation
Correct answer: (17)th
The general term is (\frac{1}{3n}), and (\frac{1}{51}<\frac{1}{50}). So the first such term is the (17)th.
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What is the correct answer to this question?
(17)th
Why is this the correct answer?
The general term is (\frac{1}{3n}), and (\frac{1}{51}<\frac{1}{50}). So the first such term is the (17)th.
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Sequences.
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