अनुक्रम \(2,6,12,20,\ldots\) में (100) से छोटे कितने पद हैं?

In the sequence \(2,6,12,20,\ldots\), how many terms are less than (100)?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

A. (9)

Step 1

Concept

Here (a_n=n(n+1)), and \(9\times10=90\) while \(10\times11=110\). So (9) terms are less than (100).

Step 2

Why this answer is correct

The correct answer is A. (9). Here (a_n=n(n+1)), and \(9\times10=90\) while \(10\times11=110\). So (9) terms are less than (100).

Step 3

Exam Tip

यहाँ (a_n=n(n+1)) है और \(9\times10=90\) जबकि \(10\times11=110\) है। इसलिए (9) पद (100) से छोटे हैं।

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Mathematics Answer, Explanation and Revision Hints

अनुक्रम \(2,6,12,20,\ldots\) में (100) से छोटे कितने पद हैं? / In the sequence \(2,6,12,20,\ldots\), how many terms are less than (100)?

Correct Answer: A. (9). Explanation: यहाँ (a_n=n(n+1)) है और \(9\times10=90\) जबकि \(10\times11=110\) है। इसलिए (9) पद (100) से छोटे हैं। / Here (a_n=n(n+1)), and \(9\times10=90\) while \(10\times11=110\). So (9) terms are less than (100).

Which concept should I revise for this Mathematics MCQ?

Here (a_n=n(n+1)), and \(9\times10=90\) while \(10\times11=110\). So (9) terms are less than (100).

What exam hint can help solve this Mathematics question?

यहाँ (a_n=n(n+1)) है और \(9\times10=90\) जबकि \(10\times11=110\) है। इसलिए (9) पद (100) से छोटे हैं।