रेखा (y=-6x+20) में (x) कितने बढ़ाने पर (y) (42) घटेगा?

In the line (y=-6x+20), by how much must (x) increase for (y) to decrease by (42)?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

B. (7)

Step 1

Concept

The slope is (-6), so the decrease is \(6\Delta x\). From \(6\Delta x=42\), \(\Delta x=7\).

Step 2

Why this answer is correct

The correct answer is B. (7). The slope is (-6), so the decrease is \(6\Delta x\). From \(6\Delta x=42\), \(\Delta x=7\).

Step 3

Exam Tip

ढाल (-6) है, इसलिए कमी \(6\Delta x\) होगी। \(6\Delta x=42\) से \(\Delta x=7\) है।

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Mathematics Answer, Explanation and Revision Hints

रेखा (y=-6x+20) में (x) कितने बढ़ाने पर (y) (42) घटेगा? / In the line (y=-6x+20), by how much must (x) increase for (y) to decrease by (42)?

Correct Answer: B. (7). Explanation: ढाल (-6) है, इसलिए कमी \(6\Delta x\) होगी। \(6\Delta x=42\) से \(\Delta x=7\) है। / The slope is (-6), so the decrease is \(6\Delta x\). From \(6\Delta x=42\), \(\Delta x=7\).

Which concept should I revise for this Mathematics MCQ?

The slope is (-6), so the decrease is \(6\Delta x\). From \(6\Delta x=42\), \(\Delta x=7\).

What exam hint can help solve this Mathematics question?

ढाल (-6) है, इसलिए कमी \(6\Delta x\) होगी। \(6\Delta x=42\) से \(\Delta x=7\) है।