किसी अनुक्रम में \(H_1=6\) और (H_n=H_{n-1}+(n-1)(n+1)) है। \(H_5\) का मान क्या होगा?

In a sequence, \(H_1=6\) and (H_n=H_{n-1}+(n-1)(n+1)). What is the value of \(H_5\)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

B. छप्पन(56)

Step 1

Concept

\(H_5=6+3+8+15+24=56\). In exams, simplify ((n-1)(n+1)) correctly.

Step 2

Why this answer is correct

The correct answer is B. छप्पन / (56). \(H_5=6+3+8+15+24=56\). In exams, simplify ((n-1)(n+1)) correctly.

Step 3

Exam Tip

\(H_5=6+3+8+15+24=56\) है। परीक्षा में ((n-1)(n+1)) को सही सरल करें।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

किसी अनुक्रम में \(H_1=6\) और (H_n=H_{n-1}+(n-1)(n+1)) है। \(H_5\) का मान क्या होगा? / In a sequence, \(H_1=6\) and (H_n=H_{n-1}+(n-1)(n+1)). What is the value of \(H_5\)?

Correct Answer: B. छप्पन / (56). Explanation: \(H_5=6+3+8+15+24=56\) है। परीक्षा में ((n-1)(n+1)) को सही सरल करें। / \(H_5=6+3+8+15+24=56\). In exams, simplify ((n-1)(n+1)) correctly.

Which concept should I revise for this Mathematics MCQ?

\(H_5=6+3+8+15+24=56\). In exams, simplify ((n-1)(n+1)) correctly.

What exam hint can help solve this Mathematics question?

\(H_5=6+3+8+15+24=56\) है। परीक्षा में ((n-1)(n+1)) को सही सरल करें।