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If (y=85-kx) is linear decay and (k=0), what is correct about the statement?

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Answer and explanation

Correct answer: It is not decay

Substituting \(k=0\) gives \(y=85-0x=85\). Thus, \(y\) does not decrease as \(x\) changes, so the relation is not linear decay. It is a constant function with slope \(0\). Option B describes the graph, but since the question asks what is correct about decay, A is the most appropriate answer. Exam tip: In \(y=a-kx\), decay occurs only when \(k>0\), because the slope \(-k\) is then negative.

Related tags

Linear DecayConstant FunctionZero SlopeLinear EquationsPolynomials

Frequently asked questions

What is the correct answer to this question?

It is not decay

Why is this the correct answer?

Substituting \(k=0\) gives \(y=85-0x=85\). Thus, \(y\) does not decrease as \(x\) changes, so the relation is not linear decay. It is a constant function with slope \(0\). Option B describes the graph, but since the question asks what is correct about decay, A is the most appropriate answer. Exam tip: In \(y=a-kx\), decay occurs only when \(k>0\), because the slope \(-k\) is then negative.

Which subject and chapter does this question cover?

This is a Class 9 Mathematics question. Chapter: Introduction to Polynomials. Topic: Linear growth and decay.

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