If (y=70-kx) is linear decay and (k=0), what is correct about the statement?
Answer and explanation
Correct answer: It is not decay; it is constant
Putting \(k=0\) in \(y=70-kx\) gives \(y=70\). Its slope is \(0\), so \(y\) neither increases nor decreases as \(x\) changes. Linear decay requires a negative slope, whereas this graph is horizontal. Exam tip: in \(y=a-kx\), if \(k>0\), the slope \(-k\) is negative.
Frequently asked questions
What is the correct answer to this question?
It is not decay; it is constant
Why is this the correct answer?
Putting \(k=0\) in \(y=70-kx\) gives \(y=70\). Its slope is \(0\), so \(y\) neither increases nor decreases as \(x\) changes. Linear decay requires a negative slope, whereas this graph is horizontal. Exam tip: in \(y=a-kx\), if \(k>0\), the slope \(-k\) is negative.
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Introduction to Polynomials. Topic: Linear growth and decay.
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