If (y=52-kt) is linear decay and (k>0), what happens to (y) as (t) increases?
Answer and explanation
Correct answer: (y) will decrease
In (y=52-kt), the coefficient of (t) is (-k). Since (k>0), (-k) is negative. As (t) increases, (kt) increases, so a larger value is subtracted from 52; therefore, (y) decreases. (y) would remain constant only if (k=0). Exam tip: in a linear expression, a positive coefficient indicates increase, while a negative coefficient indicates decrease.
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What is the correct answer to this question?
(y) will decrease
Why is this the correct answer?
In (y=52-kt), the coefficient of (t) is (-k). Since (k>0), (-k) is negative. As (t) increases, (kt) increases, so a larger value is subtracted from 52; therefore, (y) decreases. (y) would remain constant only if (k=0). Exam tip: in a linear expression, a positive coefficient indicates increase, while a negative coefficient indicates decrease.
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Introduction to Polynomials. Topic: Linear growth and decay.
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