If (y=32+kx) is linear growth and (k=0), what is correct about the statement?
Answer and explanation
Correct answer: It is neither growth nor decay; y remains constant
Here, k is the coefficient of x, or the slope of the line. Substituting k=0 gives y=32, so y does not change when x changes. Therefore, it is neither growth nor decay; it is a constant function. For decay, the slope must be negative, i.e., k<0. Exam tip: In y=a+kx, the sign of k tells whether the quantity grows, decays, or remains constant.
Frequently asked questions
What is the correct answer to this question?
It is neither growth nor decay; y remains constant
Why is this the correct answer?
Here, k is the coefficient of x, or the slope of the line. Substituting k=0 gives y=32, so y does not change when x changes. Therefore, it is neither growth nor decay; it is a constant function. For decay, the slope must be negative, i.e., k<0. Exam tip: In y=a+kx, the sign of k tells whether the quantity grows, decays, or remains constant.
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Introduction to Polynomials. Topic: Linear growth and decay.
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