If (y=140-kx) is linear decay and (k=0), what is correct about the statement?
Answer and explanation
Correct answer: It is not decay; y is constant
Substituting k=0 gives y=140-0x=140. Thus, y does not change when x changes, so the relation is neither growth nor decay; it is a constant function. For linear decay in y=140-kx, k must be positive so that the slope −k is negative. Exam tip: substitute the given value of k first and then check the slope.
Frequently asked questions
What is the correct answer to this question?
It is not decay; y is constant
Why is this the correct answer?
Substituting k=0 gives y=140-0x=140. Thus, y does not change when x changes, so the relation is neither growth nor decay; it is a constant function. For linear decay in y=140-kx, k must be positive so that the slope −k is negative. Exam tip: substitute the given value of k first and then check the slope.
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Introduction to Polynomials. Topic: Linear growth and decay.
Student feedback
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
