यदि किसी अनुक्रम का स्पष्ट नियम \(a_n=pn^2+qn+1\) है और पहले दो पद (6) तथा (15) हैं, तो \(a_4\) का मान क्या होगा?
If the explicit rule of a sequence is \(a_n=pn^2+qn+1\) and the first two terms are (6) and (15), what is the value of \(a_4\)?
Explanation opens after your attempt
C. (45)
Concept
From the given terms, (p+q=5) and (2p+q=7), so (p=2), (q=3), and \(a_4=45\). When coefficients are unknown, first form equations using small terms.
Why this answer is correct
The correct answer is C. (45). From the given terms, (p+q=5) and (2p+q=7), so (p=2), (q=3), and \(a_4=45\). When coefficients are unknown, first form equations using small terms.
Exam Tip
दिए पदों से (p+q=5) और (2p+q=7), इसलिए (p=2), (q=3) और \(a_4=45\)। अज्ञात गुणांक हों तो पहले छोटे पदों से समीकरण बनाएं।
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