If (S(x)=s-4x) and (S(2)-S(9)=28), which conclusion is correct?
Answer and explanation
Correct answer: The condition is true for every real \(s\)
\(S(2)=s-4(2)=s-8\) and \(S(9)=s-4(9)=s-36\). Therefore, \(S(2)-S(9)=(s-8)-(s-36)=28\). The terms containing \(s\) cancel, so the condition is true for every real \(s\). Neither \(s=28\) nor \(s=4\) is a specially required value. Exam tip: In differences of function values, write both values first and check whether the parameter terms cancel.
Frequently asked questions
What is the correct answer to this question?
The condition is true for every real \(s\)
Why is this the correct answer?
\(S(2)=s-4(2)=s-8\) and \(S(9)=s-4(9)=s-36\). Therefore, \(S(2)-S(9)=(s-8)-(s-36)=28\). The terms containing \(s\) cancel, so the condition is true for every real \(s\). Neither \(s=28\) nor \(s=4\) is a specially required value. Exam tip: In differences of function values, write both values first and check whether the parameter terms cancel.
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Introduction to Polynomials. Topic: Linear growth and decay.
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