यदि (P(x)=\(x^7-8\)\(x^7+8\)-x^{14}), तो (P(x)) की डिग्री क्या है?
If (P(x)=\(x^7-8\)\(x^7+8\)-x^{14}), what is the degree of (P(x))?
Explanation opens after your attempt
C. (0)
Concept
(\(x^7-8\)\(x^7+8\)=x^{14}-64). Subtracting \(x^{14}\) leaves (-64), whose degree is (0).
Why this answer is correct
The correct answer is C. (0). (\(x^7-8\)\(x^7+8\)=x^{14}-64). Subtracting \(x^{14}\) leaves (-64), whose degree is (0).
Exam Tip
(\(x^7-8\)\(x^7+8\)=x^{14}-64) होता है। \(x^{14}\) घटाने पर (-64) बचता है जिसकी डिग्री (0) है।
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