यदि (p(x)=(a-2)x-3+5x-7) और (a=2), तो (p(x)) किस प्रकार का बहुपद बनेगा?

If (p(x)=(a-2)x-3+5x-7) and (a=2), what type of polynomial will (p(x)) become?

Explanation opens after your attempt
Correct Answer

C. रेखीय बहुपदLinear polynomial

Step 1

Concept

Putting (a=2) makes the coefficient of \(x^3\) equal to (0), leaving (5x-7). So it is a linear polynomial.

Step 2

Why this answer is correct

The correct answer is C. रेखीय बहुपद / Linear polynomial. Putting (a=2) makes the coefficient of \(x^3\) equal to (0), leaving (5x-7). So it is a linear polynomial.

Step 3

Exam Tip

(a=2) रखने पर \(x^3\) का गुणांक (0) हो जाता है और (5x-7) बचता है। इसलिए यह रेखीय बहुपद है।

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Mathematics Answer, Explanation and Revision Hints

यदि (p(x)=(a-2)x-3+5x-7) और (a=2), तो (p(x)) किस प्रकार का बहुपद बनेगा? / If (p(x)=(a-2)x-3+5x-7) and (a=2), what type of polynomial will (p(x)) become?

Correct Answer: C. रेखीय बहुपद / Linear polynomial. Explanation: (a=2) रखने पर \(x^3\) का गुणांक (0) हो जाता है और (5x-7) बचता है। इसलिए यह रेखीय बहुपद है। / Putting (a=2) makes the coefficient of \(x^3\) equal to (0), leaving (5x-7). So it is a linear polynomial.

Which concept should I revise for this Mathematics MCQ?

Putting (a=2) makes the coefficient of \(x^3\) equal to (0), leaving (5x-7). So it is a linear polynomial.

What exam hint can help solve this Mathematics question?

(a=2) रखने पर \(x^3\) का गुणांक (0) हो जाता है और (5x-7) बचता है। इसलिए यह रेखीय बहुपद है।