If (M(t)=95+6t) and (N(t)=203-6t), when will (M(t)) be (24) more than (N(t))?
Answer and explanation
Correct answer: \(t=11\)
The required condition is \(M(t)=N(t)+24\). Thus, \(95+6t=203-6t+24\), so \(12t=132\) and \(t=11\). Checking: \(M(11)=161\) and \(N(11)=137\), giving a difference of \(24\). At \(t=10\), the difference is only \(12\). Exam tip: translate “24 more than” as \(M-N=24\).
Frequently asked questions
What is the correct answer to this question?
\(t=11\)
Why is this the correct answer?
The required condition is \(M(t)=N(t)+24\). Thus, \(95+6t=203-6t+24\), so \(12t=132\) and \(t=11\). Checking: \(M(11)=161\) and \(N(11)=137\), giving a difference of \(24\). At \(t=10\), the difference is only \(12\). Exam tip: translate “24 more than” as \(M-N=24\).
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Introduction to Polynomials. Topic: Linear growth and decay.
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