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If (L(t)=16+3t), what is the value of (L(5)-L(2))?
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Answer and explanation
Correct answer: 9
L(5)=16+3(5)=31 and L(2)=16+3(2)=22. Therefore, L(5)-L(2)=31-22=9. The constant term 16 cancels in the difference; only the rate 3 per unit and the 3-unit change in t matter. Exam tip: for a linear expression a+bt, use L(x)-L(y)=b(x-y).
Frequently asked questions
What is the correct answer to this question?
9
Why is this the correct answer?
L(5)=16+3(5)=31 and L(2)=16+3(2)=22. Therefore, L(5)-L(2)=31-22=9. The constant term 16 cancels in the difference; only the rate 3 per unit and the 3-unit change in t matter. Exam tip: for a linear expression a+bt, use L(x)-L(y)=b(x-y).
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Introduction to Polynomials. Topic: Linear growth and decay.
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