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Class 9MathematicsIntroduction to PolynomialsLinear growth and decayEasyLevel 40
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If (K(t)=160-8t), what is the value of (K(0)-K(12))?

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Answer and explanation

Correct answer: 96

Here, K(0)=160-8(0)=160 and K(12)=160-8(12)=64. Therefore, K(0)-K(12)=160-64=96. Option 64 is the value of K(12), not the difference. Exam tip: in linear decay, 8×12=96 directly gives the total decrease.

Related tags

Linear DecayLinear FunctionPolynomialsSubstitutionRate Of Change

Frequently asked questions

What is the correct answer to this question?

96

Why is this the correct answer?

Here, K(0)=160-8(0)=160 and K(12)=160-8(12)=64. Therefore, K(0)-K(12)=160-64=96. Option 64 is the value of K(12), not the difference. Exam tip: in linear decay, 8×12=96 directly gives the total decrease.

Which subject and chapter does this question cover?

This is a Class 9 Mathematics question. Chapter: Introduction to Polynomials. Topic: Linear growth and decay.

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