If \(a_n=\frac{2n-1}{3n+1}\), what will be the simplified value of \(a_8\)?
Answer and explanation
Correct answer: \(\frac{3}{5}\)
Given \(a_n=\frac{2n-1}{3n+1}\). Substituting \(n=8\), \(a_8=\frac{2(8)-1}{3(8)+1}=\frac{15}{25}=\frac{3}{5}\). Hence, option B is correct. A value such as \(\frac{5}{9}\) may result from incorrect substitution or simplification. Exam tip: substitute \(n\) carefully in both the numerator and denominator, then reduce the fraction.
Frequently asked questions
What is the correct answer to this question?
\(\frac{3}{5}\)
Why is this the correct answer?
Given \(a_n=\frac{2n-1}{3n+1}\). Substituting \(n=8\), \(a_8=\frac{2(8)-1}{3(8)+1}=\frac{15}{25}=\frac{3}{5}\). Hence, option B is correct. A value such as \(\frac{5}{9}\) may result from incorrect substitution or simplification. Exam tip: substitute \(n\) carefully in both the numerator and denominator, then reduce the fraction.
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Sequences.
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