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If (a^2=1521) then what is the positive value of (a)?

Answer and explanation

Correct answer: 39

Since \(a^2=1521\), we have \(a=\pm\sqrt{1521}=\pm39\), because \(39^2=1521\). The question asks for the positive value, so \(a=39\). Remember that a positive perfect square has two square roots, but its positive square root is the positive one.

Related tags

ExponentsSquare RootsNumber SystemsPerfect SquaresMathematicsClass 9 Mcq

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