Find the sum of the first (75) natural numbers.
Answer and explanation
Correct answer: 2850
The sum of the first \(n\) natural numbers is \(\frac{n(n+1)}{2}\). Substituting \(n=75\), we get \(\frac{75\times 76}{2}=75\times 38=2850\). The value \(2775\) is the sum of the first 74 natural numbers, so it is a close but incorrect option. Exam tip: In the formula, remember to use \(n+1\) along with \(n\).
Frequently asked questions
What is the correct answer to this question?
2850
Why is this the correct answer?
The sum of the first \(n\) natural numbers is \(\frac{n(n+1)}{2}\). Substituting \(n=75\), we get \(\frac{75\times 76}{2}=75\times 38=2850\). The value \(2775\) is the sum of the first 74 natural numbers, so it is a close but incorrect option. Exam tip: In the formula, remember to use \(n+1\) along with \(n\).
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Sum of first n natural numbers.
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