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Find the sum of the first (72) natural numbers.

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Answer and explanation

Correct answer: 2628

The sum of the first \(n\) natural numbers is \(S_n=\frac{n(n+1)}{2}\). Hence, \(S_{72}=\frac{72\times73}{2}=36\times73=2628\). Therefore, 2628 is correct. A value such as 2618 can result from an arithmetic error in multiplication or addition. Exam tip: when \(n\) is even, divide \(n\) by 2 first to simplify the calculation.

Related tags

Natural NumbersSum FormulaArithmetic ProgressionSequences And ProgressionsClass 9 Mathematics

Frequently asked questions

What is the correct answer to this question?

2628

Why is this the correct answer?

The sum of the first \(n\) natural numbers is \(S_n=\frac{n(n+1)}{2}\). Hence, \(S_{72}=\frac{72\times73}{2}=36\times73=2628\). Therefore, 2628 is correct. A value such as 2618 can result from an arithmetic error in multiplication or addition. Exam tip: when \(n\) is even, divide \(n\) by 2 first to simplify the calculation.

Which subject and chapter does this question cover?

This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Sum of first n natural numbers.

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